Question

1. a) A particle is moving in a circular path of radius “ r ”. What is the displacement of the particle after half a circle?
b) From the given Velocity-Time graph (figure)

Answer 1

Answer:

hey mate !!

here is your answer !!

Answer

=>> 2

in the questions given value of a is equal to zero.and the value of b is equal to minus 1.

in the questions given expression is

{a}^{2} + ab + 2a

2

+ab+2

in the given expression putting the values of a and b.

\begin{gathered} = > > {0}^{2} + 0 \times 1 + 2 \\ \\ = > > 0 + 0 + 2 \\ \\ = > > 0 + 2 \\ \\ = > > 2\end{gathered}

=>>0

2

+0×1+2

=>>0+0+2

=>>0+2

=>>2

therefore 2 is the values of given expression .

hope it's help you

Answer 2

 Given, after half the circle, the particle will reach the diametrically opposite point i.e., from point A to point 6. And we know displacement is shortest path between initial and final point. Hence, the displacement after half circle is 2r.