Question

1. a) A uniform half meter rule balances horizontally on a knife edge at 29 cm mark
when a weight of 2 gf is suspended from one end.
(i) Draw a diagram of the arrangement.
(ii) What is the weight of the half meter rule?

Answer 1

ANSWER

(ii) The center of gravity of a uniform half meter

rule is 25 cm.

The rule balances horizontally on a knife edge at 29 cm mark when a weight of 20 kgf is suspended from one end.

The difference in the center of gravity and the point of balance=29−25=4cm(Y)

The weight is suspended at one of the extremes,

Let us assume at the 50 cm end.

Therefore, the distance from the point of knife edge to the weight =50−29=21cm(X)

Weight of meter rule =

Y

X

× Suspended weight

∴ Weight of meter rule =

4

21

×20=105 kgf

solution

Answer 2

Answer:

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