1] A ABC
A ABC ~ A PQR, A (A ABC) = 16, A (A PQR) = 25 then fill in the blanks.
Solution - A ABC
ΔΡQR
A (A ABC)
A (A PQR)
(Theorem of areas of similar triangles)
16.
AB2
PQ2
25
AB
(Taking
(Taking square roots)
PQ
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Answer:
AB/PQ=4/5 are of triangle =square of side
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