Question

1. A ABC and A DBC are two isosceles triangles on
the same base BC and vertices A and D are on the
same side of BC (see Fig. 7.39). If AD is extended
to intersect BC at P, show that
D
(i) A ABD=AACD
(ii) A ABP A ACP
B
P
(iii) AP bisects LA as well as Z D.
Fig. 7.39
(iv) AP is the perpendicular bisector of BC.

Answer 1

Answer:

3 one is your answer bro please believe me

Answer 2

Answer:

Answer

Step-by-step explanation:

triangles on

the same base BC and vertices A and D are on the

same side of BC (see Fig. 7.39). If AD is extended

to intersect BC at P, show that

D

(i) A ABD=AACD

(ii) A ABP A ACP

B

P

(iii) AP bisects LA as well as Z D.

Fig. 7.39

(iv) AP is the perpendicular bisector of BC.

hope it helps you