1. A ABC and A DBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC (see Fig. 7.39). If AD is extended to intersect BC at P, show that
(1) ΔΑΒDeΔΑCD
(2) A ABP = A ACP
(3) AP bisects Z A as well as ZD
(4) AP is the perpendicular bisector of BC.
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