Question

1. A ABC and A DBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC (see Fig. 6.39). If AD is extended to intersect BC at P, show that

(i) A ABD AACD (ii) A ABPE A ACP (iii) AP bisects Z A as well as D. (iv) AP is the perpendicular bisector of BC.​

Answer 1

Step-by-step explanation:

In Fig. 6.21, AC = AE, AB = AD and angle BAD = EAC. Show that BC = DE

Answer 2

Step-by-step explanation:

here this is the correct answer!!