Math, asked by jeeom9379, 8 months ago

1. A alone can finish a piece of work in
12 days and B alone can do it in 15 days.
If both of them work at it together, how
much time will they take to finish it ?​

Answers

Answered by Anonymous
1

Step-by-step explanation:

A can do a work in = 20 days

Let B can do the work in =X days

Both A and B can do the work in = 1/12 days

Therefore 1/20 + 1/X= 1/12

So 12 (X+20) = 20 X;

So 8X= 240 ; X= 30.

Therefore “B” can do the work alone in 30 - days.

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Another Simple Method:

In 12- days A- can complete= 12/20= 3/5- part of the work.

So in 12- days B- can complete (1–3/5) = 2/5- part of the work.

So complete work can be done by B- alone in 12÷ (2/5)= 12 x5/2= 30- days.

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