Question

1. (a) An iron ball requires 5000 J heat energy to
raise its temperature by 10°C. Calculate the
heat capacity of the iron ball.
(b) If mass of ball is 1:1 kg, find the specific heat
capacity of iron.



The ans should be:-
a.
$500 J{K}^{ - 1}$
b.
$455 J {kg}^{ - 1} {K}^{ - 1}$
I am not getting how to solve it...so pls help​

Answer 1

Given :-

Mass of ball = 1.1 kg

Change in temperature = 10°C or 10K

Heat required = 5000J

To Find :-

A) Hear capacity of iron ball

B) Specific heat capacity of iron ball.

Solution :-

A) Heat capacity is defined as the heat required to increase temperature of a substance by 1°C or 1K.

Formula : Q = Hc × ∆T

By substituting the given values :-

$\longrightarrow \sf Q = Hc \times \triangle T \\\\\longrightarrow 5000 = Hc \times 10 \\\\\longrightarrow \bf Hc = 500 JK^{-1}$

B) Specific heat is defined as the heat required to increase temperature of 1unit substance by 1°C or 1K.

Formula : Q = m × c × ∆T

By substituting the given data :-

$\longrightarrow \sf Q = m \times c \times \triangle T \\\\\longrightarrow 5000 = 1.1 \times c \times 10 \\\\\longrightarrow c = \dfrac{500}{1.1 }\\\\\longrightarrow \bf c = 455 J kg^{-1}K^{-1}$

Answer 2

Answer:

Given :-

Mass of ball = 1.1 kg

Change in temperature = 10°C or 10K

Heat required = 5000J

To Find :-

A) Hear capacity of iron ball

B) Specific heat capacity of iron ball.

Solution :-

A) Heat capacity is defined as the heat required to increase temperature of a substance by 1°C or 1K.

Formula : Q = Hc × ∆T

By substituting the given values :-

⟶Q=Hc×△T

⟶5000=Hc×10

⟶Hc=500JK

−1

B) Specific heat is defined as the heat required to increase temperature of 1unit substance by 1°C or 1K.

• Formula : Q = m × c × ∆T

By substituting the given data :-

⟶Q=m×c×△T

⟶5000=1.1×c×10

⟶c=

1.1

500

⟶c=455Jkg

−1

K

−1