Question

1) A and B run around a circular
track of length 700m starting from
same point fimutane only in opposite
directions. It Aruns at a speed of
6mls and B runs at a speed of
8 mls when they meet at staating
point
again
1) 50 sec
2) 100 sec
3) 140 sec
4) 350 S​

Answer 1

Question :-- ) A and B run around a circular track of length 700m starting from same point fimutane only in opposite

directions. It Aruns at a speed of 6m/s and B runs at a speed of 8 m/s . when they meet at starting point again..

Answer :---

it is given that, both are running around a circular track in Opposite Direction .

So , in opposite direction Speed Add.

Hence, Usual Speed will be = 6+8 = 14m/s.

Now, Distance = Length of circular Track = 700m.

So, Time they will take to meet again , = Distance / usual speed .

→ Time = 700/14

→ Time = 50 seconds .

Hence, both will meet at starting point after 50 sec.

Answer 2

Answer:

$\bold\green{Time\:to\:meet}$ = $\small{\boxed{\bold{1)50\:sec}}}$

Explanation:

Given:-

• Total distance = 700 m
• Speed of A = $\bold{6\:{ms}^{-1}}$
• Speed of B = $\bold{8\:{ms}^{-1}}$
• Time taken to meet each other = ?

Speed of A and B will add because they are running in opposite directions.

$\Rightarrow\sf Total\:speed = ( 6 + 8 ) \:{ms}^{-1} \\\\\Rightarrow{\boxed{\bold{Total\:speed = 14\:{ms}^{-1} }}}$

As length of circular track = 700 m, and they will have to run 700 m to meet each other.That's why:-

${\boxed{\bold{Total\:distance=700\:m}}}$

$\rule{300}{1}$

$\bigstar{\boxed{\bold{Time =\dfrac{Distance}{Speed} }}}$

$\sf *Substituting\:values:-$

$\Rightarrow\sf Time =\cancel{\dfrac{700\:m}{14\:{ms}^{-1}}} \\\\\Rightarrow{\boxed{\bold{Time = 50\:s}}}$

$\therefore\bold{Time\:taken\:to\:meet\:each\:other = 50\:s}$