Question

1. A and B try to hit a target. The probability that A hits the target is 7/10 and the probability that B hits
the target is 4/10 .if these two events are independent, the probability that B hits the target, given that
the target is hit,is​

Answer 1

Answer:

Step-by-step explanation:

A HIT THE TARGET=7/10

B HIT THE TARGET=4/10

A NOT HIT THE TARGET=3/10

B NOT HIT THE TARGET=6/10

PROBABILITY OF NOT HITTING =3/10*6/10=18/100

Answer 2

Probability of A hit the target = 4/10;

Probability of B hit the target = 7/10;

The probability hitting the target only once = P(A)[1-P(B)] * P(B)[1- P(A)]

= 4/10{4}{10} (1-\frac{7}{10} ) + \frac{7}{10}(1-\frac{4}{10} )\\;

= \frac{4}{10}*\frac{3}{10} + \frac{7}{10}*\frac{3}{10};

The probability hitting the target only once = \frac{33}{100};