Question

1/a-b +1/b-a =? find the value

Answer 1

Answer:

1/a-b+1/b-a solve this by taking lcm=b-a+a-b/(a-b)(b-a) solve this u will get your required answer

Step-by-step explanation:

Answer 2

QUESTION :

1/a-b +1/b-a =? find the value

ANSWER :

1/a-b +1/b-a

= (1/(a-b)) + (1/(b-a))

now by taking minus sign in common

we get

(1/(a-b)) + (1/(b-a))

= (1/(a-b)) + (1/-(-b+a))

= (1/(a-b)) + (1/-(a-b))

but as we know that

X/(-y) = -(X)/y

so we get

(1/(a-b)) + (1/-(a-b))

= (1/(a-b)) + (-1/(a-b))

= (1/(a-b)) -(1/(a-b))

now as denominator are same

(1/(a-b)) -(1/(a-b))

= (1-1)/(a-b)

= 0/(a-b)

but as we know that

zero divided by anything except 0 is 0

so

0/(a-b)

= 0

hence

(1/(a-b)) + (1/(b-a))= 0

NOTE :

While solving such questions

try to find some similarities between the terms

as we find in the given question that the terms were same but differ in sign

so we make the sign which were needed to us by taking minus sign common