Question

1-(a-b) ²=(1+a-b)x_______ a) (1-a-b) b)( -1+a-b) c) (1-a+b) d) (1+a+b)
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Answer 1

Answer:

$1 - {(a - b)}^{2} = (1 + a - b) \times x \\ \\ = > 1 - ( {a}^{2} - 2ab + {b}^{2} ) = (1 + a - b) \times x \\ \\ = > 1 - {a}^{2} + 2ab - {b}^{2} =( 1 + a - b) \times x \\ \\ = > \frac{1 - {a}^{2} + 2ab - {b}^{2} }{1 + a - b} = x \\ \\ = > \frac{1 - {(a - b)}^{2} }{1 + (a - b)} = x \\ \\ = > \frac{1 - a - b}{1} = x \\ \\ = > 1 - a - b = x$

☑️ so option a is ☑️

hope this much helps uh ❣️