Question

(1,a),(b, 2) are conjugate points with respect to the circle x^2+y^2=25 , then 4a+2b=​

Answer 1

Given :  (1, a), (b, 2) are conjugate points with  respect to the circle

x² + y²   = 25  

To Find :  4a + 2b

Solution:

x² + y²   = 25  

=> x² + y²   =5²

x₁ , y₁   and x₂ , y₂ are conjugate to circle x² + y² = r²

if  x₁.x₂ + y₁.y₂  = r₂

=> 1b +  a(2)  = 5

=> b + 2a  = 5

=> 2a + b = 5

=> 2(2a + b) = 2 (5)

=> 4a + 2b = 10

4a + 2b = 10

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