(1+a+b)^3 expand the following.
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1
Answer:
(1+a+b)3
=(1+a+b)*(1+a+b)*(1+a+b)
=(1+a+b)(a2+2ab+b2+2a+2b+1)
=(1)(a2)+(1)(2ab)+(1)(b2)+(1)(2a)+(1)(2b)+(1)(1)+(a)(a2)+(a)(2ab)+(a)(b2)+(a)(2a)+(a)(2b)+(a)(1)+(b)(a2)+(b)(2ab)+(b)(b2)+(b)(2a)+(b)(2b)+(b)(1)
=a2+2ab+b2+2a+2b+1+a3+2a2b+ab2+2a2+2ab+a+a2b+2ab2+b3+2ab+2b2+b
=a3+3a2b+3ab2+b3+3a2+6ab+3b2+3a+3b+1
Answered by
1
Answer:
Step-by-step explanation:
(a + b + c)2 = a3+ b3+ c3 +3a^2b+3a^2c+3b^2a+3b^2c+3c^2a+3c^2b+6abc
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