Question

1) (a+b)* (a² - ab +b²)​

Answer 1

Step-by-step explanation:

(a+b)(a-b) = a² - b² ----{- ab + ab = 0 }. Hence the required solution is (a+b)(a-b)= a²-b². Let a = b+k ; k is a real number. (a+b)(a-b) i.e( a^n- b^n) is always divisible by( a+b) and( a-b), If n is even.

Answer 2

Answer:

(a+b)²+(a-b) ² = a²+b²+2ab-a²-b²+2ab = 4ab

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