Question

1+a+b+ab can be written as​

Answer 1

Solution :

This term can be expressed as -

1 + a + b + ab

>> 1 + a + b(1 + a)

>> (1 + a) + b(1 + a)

>> (1 + a)( 1 + b)

This might seem basic but is often a lot useful in various questions .

Additional Information :

$\boxed{\begin{minipage}{7 cm}\boxed{\bigstar\:\:\textbf{\textsf{Algebric\:Identity}}\:\bigstar}\\\\1)\bf\:(A+B)^{2} = A^{2} + 2AB + B^{2}\\\\2)\sf\: (A-B)^{2} = A^{2} - 2AB + B^{2}\\\\3)\bf\: A^{2} - B^{2} = (A+B)(A-B)\\\\4)\sf\: (A+B)^{2} = (A-B)^{2} + 4AB\\\\5)\bf\: (A-B)^{2} = (A+B)^{2} - 4AB\\\\6)\sf\: (A+B)^{3} = A^{3} + 3AB(A+B) + B^{3}\\\\7)\bf\:(A-B)^{3} = A^{3} - 3AB(A-B) + B^{3}\\\\8)\sf\: A^{3} + B^{3} = (A+B)(A^{2} - AB + B^{2})\\\\\end{minipage}}$

Answer 2

Question :-

1+a+b+ab can be written as

Solution :

This term can be expressed as -

1 + a + b + ab

>> 1 + a + b(1 + a)

>> (1 + a) + b(1 + a)

>> (1 + a)( 1 + b)

↪️ Thanks

↪️ llMichhChocoll