1.(a-b)+(b-c)+(c-a)
2.(a+b)(a-b)+(b+c)(b-c)+(c+a)(c-a)
Answers
Answered by
3
Required Answer:-
Given To Simplify:
- (a - b) + (b - c) + (c - a)
- (a + b)(a - b) + (b + c)(b - c) + (c + a)(c - a)
Solution:
Question 1:
(a - b) + (b - c) + (c - a)
= a - b + b - c + c - a
= a - c + c - a
= a - a
= 0
Answer: 0
Question 2:
(a + b)(a - b) + (b + c)(b - c) + (c + a)(c - a)
= (a² - b²) + (b² - c²) + (c² - a²) [Using identity (a + b)(a - b) = a² - b²]
= a² - b² + b² - c² + c² - a²
= a² - a² + b² - b² + c² - c²
= 0 + 0 + 0
= 0
Answer: 0
Answers:
- 0
- 0
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