Math, asked by skmijanurop, 3 months ago

1.(a-b)+(b-c)+(c-a)
2.(a+b)(a-b)+(b+c)(b-c)+(c+a)(c-a)

Answers

Answered by anindyaadhikari13
3

Required Answer:-

Given To Simplify:

  1. (a - b) + (b - c) + (c - a)
  2. (a + b)(a - b) + (b + c)(b - c) + (c + a)(c - a)

Solution:

Question 1:

(a - b) + (b - c) + (c - a)

= a - b + b - c + c - a

= a - c + c - a

= a - a

= 0

Answer: 0

Question 2:

(a + b)(a - b) + (b + c)(b - c) + (c + a)(c - a)

= (a² - b²) + (b² - c²) + (c² - a²) [Using identity (a + b)(a - b) = a² - b²]

= a² - b² + b² - c² + c² - a²

= a² - a² + b² - b² + c² - c²

= 0 + 0 + 0

= 0

Answer: 0

Answers:

  1. 0
  2. 0
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