Question

1/(a+b+c) = 1/a + 1/b + 1/c ​

Answer 1

Answer:

c= -a , c= -b

Step-by-step explanation:

1/a+b+c-1/c= 1/a+1/b

c-(a+b+c)/(a+b+c)c= a+b/ab     (LCM)

c-a-b-c/(a+b+c)c=a+b/ab

-a-b/(a+b+c)c=a+b/ab    ( c gets canceled)

-(a+b)/(a+b+c)c=a+b/ab

-1/(a+b+c)c=1/ab      (a+b on both sides gets canceled)

-ab=(a+b+c)c           (cross multiplication)

-ab= ac+bc+$c^{2}$

0=ac+$c^{2}$+bc+ab

0= c(a+c)+b(a+c)

(c+b), (c+a)

∴ c= -b , c= -a

MARK ME AS BRAINLIEST :-)

Hope this helps