Math, asked by barotkrish23, 6 months ago

1/a+b+c = 1/a+ 1/b+1/c​

Answers

Answered by bhumikabehera16
4

Step-by-step explanation:

1/a+b+c =1/a + 1/b + 1/X

1/a+b+c -1/X= 1/a +1/b

x-a-b-x/ ax +bx + X sq. = b+ a/ ab

-a-b/ X sq +aX + bx = a+b/ ab

-(a+b)(ab) =(a+b)(X sq. +ax+bx)

-(a+b)/(a+b) (ab) = a sq.+ ax + bx

-ab = X. sq. + ax+ bx

x sq.( a+b) x +ab =0

xsq. + ax + bx + ab =0

X(X+a)+b ( X+a ) =0

(X+b) (X+a) =0

X= -b

X=-a...

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