Math, asked by aatikasiddiqui608, 24 days ago

1/a+b+c-1/X=1/a+1/b solve (quadratic equations)​

Answers

Answered by khanchild29
0

Step-by-step explanation:

1/a+b+c -1/x= 1/a+b/b

1/a+b+c - 1/x=1/(a+b)b

(a+b)b -(a+b+c)/(a+b+c)(a+b)b= 1/x

x(a+b)b -(a+b+c)= (a+b+c)(a+b)b

x=(a+b+c)(a+b)b/(a+b)b-(a+b+c)

Answered by LindaCournel
1

Answer:

-(a+b)/ab

Step-by-step explanation:

1 /( a+b+c) -1/x = 1/a + 1/b

--》1/(a+b+c) -1/x = (b+a)/ab

--》1/(a+b+c) - (b+a)/ab = 1/x

--》 [ab-{(b+a)(a+b+c)}] / ab(a+b+c) = 1/x

--》 [ab-{b( a+b+c) +a(a+b+c)}] / ab(a+b+c) = 1/x

--》{ ab -( a²+ab+ac+ab+b²+ab)} / ab(a+b+c) = 1/x

--》 ( ab-a²-ab-ac-ab-b²-ab)/ab(a+b+c) = 1/x

--》 ( -a²-b²-2ab - bc-ac)/ab(a+b+c) = 1/x

--》 {-( a²+b²+2ab) -c (a+b)/ ab(a+b+c)= 1/x

--》 {-(a+b)² -c(a+b) } / ab(a+b+c) = 1/x [ take -(a+b) common]

--》 -(a+b) (a+b+c)/ ab(a+b+c) = 1/x [(a+b+c) gets cancelled]

--》 -(a+b) / ab = 1/x (cross multiplication)

--》 x{-(a+b)}= ab

--》 x = ab/-(a+b) ans.

hope it helps you though I'm a bit late to reply lol

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