Question

1.A,B,C and D are
points on a circle AC and BD
intersect at a point E. Such
that BEC is equal to 130 and
ECD is equal to 20 degree find
angle BAC and angle ABE? ​

Answer 1

Answer:

DEC = 5

CDE = 11

BAC = 110

Step-by-step explanation:

BEC + DEC = 180. ( linear pair of complimentary)

130 + DEC = 180

DEC = 5

In triangle DEC + ECD + CDE = 180 (angle sum property)

50 +20 + CDE = 180

CDE = 11

By theorem of circle BAC = CDA

BAC = CDE = 110

BAC = 110

Hope it helps you!!