Question

1.(a-b)(c-d) + (a-b)(c+d) +2(ac+bd)

Answer 1

it's wrong it can be written as

(a-b)(c-d)

Answer 2

so your answer is

(a-b)(c-d)+(a-b)(c+d)+2(ac+bd)

=a(c-d)-b(c-d)+a(c+d)-b(c+d)+2(ac)+2(bd)

=1ac-1ad-1bc+1bd+1ac+1ad-1bc-1bd+2ac+2bd

=1ac+1ac+2ac-1ad+1ad-1bc-1bc+1bd-1bd+2bd

=4ac-2bc+2bd

I did it step by step

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