(1/a+b+x)=1/a+1/b+1/c
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1/(a+b+c)≠ 1/a + 1/b + 1/c
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in place of 1/c there is 1/x
1/a+b+x = 1/a +1/b +1/x
1/a+b+x - 1/x = 1/a + 1/b
x-(a+b+x)/x(a+b+x) = a+b/ab
x- a-b-x/ x(a+b+x) = a+b/ab
-(a+b)/ x(a+ b + x) = a+b/ab
-1/ x(a+b+x) = 1/ ab
xa+ xb +x^2 = -ab
x^2 + xa +xb + ab= 0
taking common
x(x+a) +b (x+a)
(x+a) ,(x+b)
i.e,
x = -a or. x= -b
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