Math, asked by bistusaha4g, 7 months ago

(1/a+b+x)=1/a+1/b+1/c

Answers

Answered by tarracharan
2

what is the question?

if u post clearly I will answer

1/(a+b+c) 1/a + 1/b + 1/c

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Answered by isha623
0

in place of 1/c there is 1/x

1/a+b+x = 1/a +1/b +1/x

1/a+b+x - 1/x = 1/a + 1/b

x-(a+b+x)/x(a+b+x) = a+b/ab

x- a-b-x/ x(a+b+x) = a+b/ab

-(a+b)/ x(a+ b + x) = a+b/ab

-1/ x(a+b+x) = 1/ ab

xa+ xb +x^2 = -ab

x^2 + xa +xb + ab= 0

taking common

x(x+a) +b (x+a)

(x+a) ,(x+b)

i.e,

x = -a or. x= -b

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