1/(a+b+x) = 1/a+1/b+1/x. Find tje value of X.???
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Hii friend,
We have:
1/(A+B+X) = 1/A + 1/B + 1/X
1/(A+B+X) -1/X = 1/A + 1/B
X-(A+B+X)/X(A+B+X) = B+A/AB
-(A+B)/X(A+B+X) = (A+B)/AB
-1/X(A+B+X) = 1/AB. [ on dividing both sides by(A+B)]
THEREFORE,
X(A+B+X)= -AB. [ by cross multiplication]
X² + AX + BX + AB = 0
X(X+A) + B(X+A) = 0
(X+A) = 0 or (X+B) = 0
X = -A. or X = -B.
HENCE,
-A AND -B ARE THE ROOTS OF THE EQUATION.
HOPE U WILL UNDERSTAND..... :-)
We have:
1/(A+B+X) = 1/A + 1/B + 1/X
1/(A+B+X) -1/X = 1/A + 1/B
X-(A+B+X)/X(A+B+X) = B+A/AB
-(A+B)/X(A+B+X) = (A+B)/AB
-1/X(A+B+X) = 1/AB. [ on dividing both sides by(A+B)]
THEREFORE,
X(A+B+X)= -AB. [ by cross multiplication]
X² + AX + BX + AB = 0
X(X+A) + B(X+A) = 0
(X+A) = 0 or (X+B) = 0
X = -A. or X = -B.
HENCE,
-A AND -B ARE THE ROOTS OF THE EQUATION.
HOPE U WILL UNDERSTAND..... :-)
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