1/a+b-x = 1/b+ 1/b+ 1/x solve for x
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1
Answer:
1/(a+b-x) = 1/b+ 1/b+ 1/x
= 2 / b + 1/ x
= ( 2x + b ) / bx
bx = ( 2x + b ) (a+b-x)
= 2xa + 2bx - 2x^2 + ab + b^2 - xb
0 = 2xa - 2x^2 + ab + b^2
2x^2 - 2xa = ab + b ^2
2x^2 - 2xa - ab - b^2 = 0
Answered by
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Step-by-step explanation:
multiply both sides of the equation by the LCM
abx x 1 + abx(b-x) =abx x1 + abx x1 +abx x 1
a. b. b. x
bx + ab2x -abx2 =ax + ax + ab
bx + ab2x -abx2 =2ax + ab
bx+ab2x- abx2-2ax =ab
x(b + ab2 - abx -2a) =ab
x= ab.
b + ab2 - abx -2a
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