1. A bag contains 12 balls out of which X balls are white. If one ball is taken out from the bag, find the probability of getting a white ball. If 6 more white balls are added to the bag and the probability now for getting a white ball is double the previous one, find the value ofx
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Step-by-step explanation:
no of balls=12
no of white balls =x
p(white ball) = no. of favourable outcomes/no of total possible outcomes
= x/12----(1)
2)
if 6 more white balls are put in the bag
no of total balls = 18
no of white balls =x+6
p(white balls)= (x+6)/18---(2)
therefore
(x+6)/18 = 2*x/12
(x+6)/18 =x/6
x+6 = 18x/6
x+6=3x
6=3x-x
6=2x
2x=6
x=6/2
x=3
Answered by
0
Answer: Here is your Answer
Step-by-step explanation:
no of balls=12
no of white balls =x
p(white ball) = no. of favourable outcomes/no of total possible outcomes
= x/12----(1)
2)
if 6 more white balls are put in the bag
no of total balls = 18
no of white balls =x+6
p(white balls)= (x+6)/18---(2)
therefore
(x+6)/18 = 2*x/12
(x+6)/18 =x/6
x+6 = 18x/6
x+6=3x
6=3x-x
6=2x
2x=6
x=6/2
x=3
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