Question

1. A bag contains hundred 50p coins, fifty Rs.1
coins, twenty Rs 2 coins and ten Rs 5 coins. If it is
equally likely that one of the coins will fall out when
the bag is turned upside down, what is the
probability that the coin will NOT be a Rs. 5 coin?
(A) 1/18
(B) 10/18
(C) 17/18
(D) 5/18​

Answer 1

Answer:

Total no. of coins in the bag is 180

Solution(i):

No. of 50p coins in bag is 100

Let E be the event of drawing a coin from piggy

We know that, Probability P(E) =

(Total no.of possible outcomes)

(No.of favorable outcomes)

=

180

100

=

9

5

Therefore,Probability that a 50p coin wins =

9

5

Solution(ii):

No. of coins with value >Rs. 1 in piggy is 30

Let E be the event of drawing a coin from bag

We know that, Probability P(E) =

(Total no.of possible outcomes)

(No.of favorable outcomes)

=

180

30

=

6

1

Therefore,Probability that a coin with value >Rs.1 falls =

6

1

Solution(iii):

No. of coins with value <Rs 5 in bag is 170

Let E be the event of drawing a coin from piggy

We know that, Probability P(E) =

(Total no.of possible outcomes)

(No.of favorable outcomes)

=

180

170

=

18

17

Therefore,Probability that a coin with value <Rs.5 falls =

18

17

Answer 2

HEY MATE THIS IS IR ANSWER

Number of 50 ps coins = 100

Number of Re. 1 coins = 50

Number of Rs. 2 coins = 20

Number of Rs. 5 coins = 10

∴ Total number of coins, n(S) = 180

Possibility of one Rs. 5 coin:

n(B) = 180 – 10 = 170

(∵ 10 coins are Rs. 5)

∴ Probability, P{B} = n{B}/n{S} = 170/180

⚛⚛⚛➡➡ 17/18 ⚛⚛➡➡

OPTION C