(1) A bag contains in all 50 balls. Some of them are white, some are blue
and some are red. The number of white balls is 11 times the of blue balls. The number of red balls is less than the number of white
balls. Also, the number of red balls is more than the number of blue
balls. If one of the balls is selected at random from the bag, what is the
probability that it is red ?
(2) There are three dealers A, B and C in Maharashtra. Suppose, the trade
of each of them in september 2018 was as shown in the following table.
The rate of GST on each transaction was 5%.
Read the table and answer the questions below it.
Dealer
GST
collected
on the sale
GST paid at
the time of
purchase
ITC
Tax paid
to the
Govt.
Tax-
balance
with the
Govt.
A Rs. 5000 Rs. 6000 Rs. 5000 Rs. 0 Rs. 1000
B Rs. 5000 Rs. 4000 Rs. 4000 Rs. 1000 Rs. 0
C Rs. 5000 Rs. 5000 Rs. 5000 Rs. 0 Rs. 0
(i) How much amount did the dealer A get by sale ?
(ii) For how much amount did the dealer B buy the articles ?
(iii) How much is the balance of CGST and SGST left with the government
that was paid by A ?
Answers
The bag contains a total of 50 balls!
Let the total white balls be W
And the total red balls be R
And the total blue balls be B
The question is too simple ,
According to the question : -
W = 11 B
Also ,
R < W
And
R > B
Total balls = 50 = W + R + B
= 11B + R + B
= 12 B + R
If B = 5 then 12B = 60
which is not possible because total balls are only 50
So B < 5
Also if B = 4
12B = 48
Then R = 50 - 48 = 2
But this is not possible because R is given greater than B
If B = 3
Then 12B = 36
So
R = 50 - 36 = 14
This is a possible case
Because W > R > B
and here ,
33 > 14 > 3
If B = 2
Then 12B = 24
Then R = 50 - 24 = 25
Which is not possible because in this case R will become greater than W but in question W > R
So only possible case is : -
B = 3
W = 11B = 33
R = 50 - (33 + 3) = 14
If one ball is selected at random then probability to get red ball is : -
Total red balls / Total balls
= 14 / 50
= 7/25
Answered by an IIT JEE ASPIRANT and all India mathematics OLYMPIAD TOPPER in class 10th
Sorry for late answer by I was talking to someone
Answer:
The bag contains a total of 50 balls!
Let the total white balls be W
And the total red balls be R
And the total blue balls be B
The question is too simple ,
According to the question : -
W = 11 B
Also ,
R < W
And
R > B
Total balls = 50 = W + R + B
= 11B + R + B
= 12 B + R
If B = 5 then 12B = 60
which is not possible because total balls are only 50
So B < 5
Also if B = 4
12B = 48
Then R = 50 - 48 = 2
But this is not possible because R is given greater than B
If B = 3
Then 12B = 36
So
R = 50 - 36 = 14
This is a possible case
Because W > R > B
and here ,
33 > 14 > 3
If B = 2
Then 12B = 24
Then R = 50 - 24 = 25
Which is not possible because in this case R will become greater than W but in question W > R
So only possible case is : -
B = 3
W = 11B = 33
R = 50 - (33 + 3) = 14
If one ball is selected at random then probability to get red ball is : -
Total red balls / Total balls
= 14 / 50
........