Question

1. A bag contains one rupee, 50 p and 25 p coins in the ratio 5:6:8 amounting number to rs 210.Find number of coins of each type​

Answer 1

Answer:

Therefore no.of 1 rupee coin

= 5 x 21

= 105

no.of 50 paise coin

= 6 x 21

= 126

no.of 25paise coin

= 8 x 21

= 168

Step-by-step explanation:

let the number of 1 re coins = 5x

let the number of 50 p coins = 6x

let the number of 25 p coins = 8x

amount of 1 re coins in Rs= 5x

amount of 50 p coins in Rs = 3x

amount of 25 p coins in Rs= 2x

total amount =210

i.e 5x+3x+2x=210

i.e 10x=210

i.e x=21

Therefore no.of 1 rupee coin=5 x 21=105

no.of 50 paise coin=6 x 21=126

no.of 25paise coin=8 x 21=168

Answer 2

Answer:

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