Question

1)A ball is gently dropped from a height of 20 m. If its velocity increases uniformly at the rate of 10 m s−2, with what velocity will it strike the ground? After what time will it strike the ground?do in note book

Answer 1

Answer:

Let us assume, the final velocity with which ball will strike the ground be ‘v’ and time it takes to strike the ground be ‘t’

Initial Velocity of ball, u =0

Distance or height of fall, s =20 m

Downward acceleration, a =10 m s-2

As we know, 2as =v2-u2

v2 = 2as+ u2

= 2 x 10 x 20 + 0

= 400

ˆ´ Final velocity of ball, v = 20 ms-1

t = (v-u)/a

ˆ´Time taken by the ball to strike = (20-0)/10

= 20/10

= 2 seconds

hope it will help your mark the answer as brainlist

Explanation:

Answer 2

Answer:

2 seconds.

hope it helps you mate.

please thank and mark my answer as brainliest .

THANK YOU SO MUCH ❤

@ ANUSHA ❤✌