Question

1.A ball is released in a hemispherical bowl. Calculate the ratio of it's translational K.E and rotational K.E at the bottom of the hemisphere.
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Answer 1

Answer:

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Answer 2

Answer:

The transnational kinetic energy is given by

K

t

=

2

1

mv

2

. . . . .(1)

Rotational kinetic energy is given by

K

r

=

2

1

Iω

2

.. . . . . . . .(2)

where, I=

5

2

mr

2

moment of inertia

ω=

r

v

angular velocity

Equation (1) becomes,

K

r

=

2

1

×

5

2

mr

2

×

r

2

v

2

K

f

=

5

1

mv

2

. . . . .(3)

Ratio,

K

r

K

t

=

mv

2

/5

mv

2

/2

=

2

5

K

t

:K

i

=5:2

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