Question

1. A ball is thrown vertically upward with the velocity 20m/s: Calculate
i How high it goes.
ii the time taken to reach the maximum height (taking aceleration due to gravity g=9.8ms)​

Answer 1

Answer:

Time to reach maximum height can be obtained from v=u+at

0=20+(−10)t

t=2s

s=ut+0.5at

2

=20(2)+0.5(−10)(2)

2

=20m

Thus, total distance for maximum height is 45 m

s=ut+0.5at

2

45=0+0.5(10)(t

′

)

2

t

′

=3s

Total time= 3+2= 5s