1. A ball is thrown vertically upwards from ground with such a speed so that it just reaches the top of a building and then falls back. If it takes 7 s for the ball to return to the hands of thrower, calculate the height of thebuilding, approximately:
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Explanation:
time of motion = 7 sec
v=u+at
u=35 m/s
height of building =u^2/2g = 1225 / 20 = 122.5/2 = 61.25 m
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