Question

1. A ball of mass 0.10kg is thrown vertically upwards with an initial velocity of 20 m/s. Calculate the maximum
potential energy it gains as it goes up.​

Answer 1

Answer:

MASS= 0.1 KG

V=0 (SINCE IT IS THROWN UP)

U=20M/S

POTENTIAL ENERGY= MGH WHERE G= 10M/S2(CONSTANY)

H= ?

FROM THE EQUATION

V2=U2+2GH

0=400+2*-10*H (ACCORDING TO RULE IF ANY THING THROWN UP G WILL BE IN MINUS)

-400=-20H

H=20M

PE=0.1*10*20

POTENTIAL ENERGY = 20J

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Explanation:

Answer 2

Answer:

20J

Explanation:

MASS= 0.1 KG

V=0 (SINCE IT IS THROWN UP)

U=20M/S

POTENTIAL ENERGY= MGH WHERE G= 10M/S2(CONSTANY)

H= ?

FROM THE EQUATION

V2=U2+2GH

0=400+2*-10*H (ACCORDING TO RULE IF ANY THING THROWN UP G WILL BE IN MINUS)

-400=-20H

H=20M

PE=0.1*10*20

POTENTIAL ENERGY = 20J