Question

1. A ball of mass ml = 5kg and a block of mass m2= 13kg are attached by a lightweight cord that passes over a frictionless pulley of negligible mass, as

shown in Figure-1 The block lies on a frictionless incline of angle(0 = 48°). Find the magnitude of the acceleration of the two objects and the tension in the cord
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Answer 1

Answer:

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Explanation:

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Answer 2

Given:

M1= 5kg

M2=13kg

Angle of inclination = 48°

To find:

Tension in the cord

Acceleration a1 of mass M1

Acceleration a2 of mass M2

Solution:

Making a Free Body Diagram for M2,

a2 is produced due to force M2g sin 48°

So, a2 = g sin48°

Also, tension T in cord is balanced by M2gcos48°

so T= M2g cos48°

For M1, writing the equation using Newton's law:

T - M1g = M1a1

or M2g cos48° - M1g = M1a1

Substituting the values of g, cos 48 and sin 48, we get:

a2= 7.4 m/s^2

a2= 7.4 m/s^2T= 85.8N

a2= 7.4 m/s^2T= 85.8Na1= 7.1m/s^2