Question

1.A bettery of 9 V is connected in series with resistors of 0.2Ω, 0.3Ω, 0.4Ω, 0.5Ω & 12Ω,resp.How much current would flow

through the 12 Ω resistor?

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Answer 1

Answer:

Given

ʀ ɪs ᴛʜᴇ ᴇϙᴜɪᴠᴀʟᴇɴᴛ ʀᴇsɪsᴛᴀɴᴄᴇ ᴏғ ʀᴇsɪsᴛᴀɴᴄᴇs 0.2 ᴏʜᴍ, 0.3 ᴏʜᴍ, 0.4ᴏʜᴍ, 0.5 ᴏʜᴍ ᴀɴᴅ 12 ᴏʜᴍ.

To find

ᴄᴜʀʀᴇɴᴛ ғʟᴏᴡ ᴛʜʀᴏᴜɢʜ 12 ᴏʜᴍ ʀᴇsɪsᴛᴏʀ

solution

ᴡᴇ ᴋɴᴏᴡ ᴛʜᴀᴛ,

ᴛʜᴇʀᴇ ɪs ɴᴏ ᴄᴜʀʀᴇɴᴛ ᴅɪᴠɪsɪᴏɴ ᴏᴄᴄᴜʀʀɪɴɢ ɪɴ ᴀ sᴇʀɪᴇs ᴄɪʀᴄᴜɪᴛ. ᴄᴜʀʀᴇɴᴛ ғʟᴏᴡ ᴛʜʀᴏᴜɢʜ ᴛʜᴇ ᴄᴏᴍᴘᴏɴᴇɴᴛ ɪs ᴛʜᴇ sᴀᴍᴇ, ɢɪᴠᴇɴ ʙʏ ᴏʜᴍ’s ʟᴀᴡ ᴀs

V= IR

I= V/R

ʀ= 0.2 + 0.3 + 0.4 + 0.5 + 12 = 13.4 ᴏʰᵐ

Potential difference, ᴠ= 9 ᴠ

ɪ= 9/13.4 = 0.671 ᴀ

Thereof, the current flow through 12ohm resistor is 0.671 ᴀ.

Explanation:

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Answer 2

Explanation:

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