Question

1. A block is thrown upwards with a kinetic energy 1).
If it goes up to a maximum height of 1 m, find the
mass of the block.​

Answer 1

Answer:

Final velocity =0

Initial v=?

a=-10m/s*s

d=1 m

From third equation of motion

v*v-u*u=2as

0-u*u=2*10*1

u*u=20

u=root20

K.E=1/2mv^2

1=1/2m*20

M=2/20

M=1/10kg

M=0.1kg

Answer 2

Answer:

0.1KG

Explanation:

KE = 1J

v = 0

g = 10m/s²

h = 1m

u = ?

m = ?

first, from 3rd eqⁿ of motion,

v²-u² = 2as

0-u² = 2gh

u² = 2*10*1

u² = 20

u = sqrt20

Now, KE = 1/2mv²

it implies, 1 = 1/2*m*20 (since, intial velocity^2 = 20 as shown above)

therefore, m = 2/20 = 1/10 = 0.1KG (ans)