Question

1. A block of mass 5:0 kg is suspended from the end of a
vertical spring which is stretched by 10 cm under the
load of the block. The block is given a sharp impulse
from below so that it acquires an upward speed of 2-0
m/s. How high will it rise ? Take g = 10 m/s​

Answer 1

Mass of the block = 5 kg.

v = 2m/sec.

Now Kinetic energy of the block is ,

(1/2) mv² .

Assume the new height of the block be h.

So the change in potential energy at the highest point is equal to Kinetic energy .

∴ mgh = (1/2)mv²

h = (1/2g)v²

h = 2² /(2×10)

h = 1/5

h = 0.2 m

or h = 20 cm.

Answer 2

Answer:

poko p id chhoti k nam se pikachu hi h