Question

1. A block of wood with a mass of 50kg is lying on a rough horizontal surface. What is the magnitude of the force exerted by the surface on the block?

Answer 1

Answer:

Here the force acting is the normal force by surface on the block

which is perpendicular to the surface of block given by weight of block F=mg =50×10=500N

here g=10m/s^2

Answer 2

The force exerted by the block of wood on the rough horizontal surface would be equal to the weight of the block of wood.

The mass 'm' of the block= 50 kg

The acceleration due to the gravity= 9.8 m/s²

The force exerted due to weight = mg

                                                       =50*9.8

                                                       = 490 N

According to Newton's third law of motion, there is an equal and opposite reaction for every action.

Hence, the magnitude of the force exerted by the surface on the block would be 490 N.