(1) A body at rest gains a velocity of 16m/s in 10s. Mass of the body is 25 kg calculate the change in momentum and net force acting on a particle
Answers
Mass of the body =10 kg
Initial velocity u=4 m/s
Final velocity v=8 m/s
Time t=2s
a) Momentum before force acts p
1
=m×u=10×4=40kg.m/s
b) Momentum after force acts p
2
=m×v=10×8=80kg.m/s
c) Gain in momentum per second =
2
40
=20kg.m/s
d) Acceleration a=
t
v−u
=
2
8−4
=2m/s
2
Force =m×a=10×2=20 N
Answer:
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Class 11
>>Physics
>>Laws of Motion
>>Solving Problems In Mechanics
>>The velocity of a body of mass 10 kg inc
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The velocity of a body of mass 10 kg increases from 4 m/s to 8 m/s when a force acts on it for 2 s.
a) what is the momentum before the force acts?
b) What is the momentum after the force acts?
c) what is the gain momentum per second?
d) What is the value of the force?
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Solution
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Mass of the body =10 kg
Initial velocity u=4 m/s
Final velocity v=8 m/s
Time t=2s
a) Momentum before force acts p
1
=m×u=10×4=40kg.m/s
b) Momentum after force acts p
2
=m×v=10×8=80kg.m/s
c) Gain in momentum per second =
2
40
=20kg.m/s
d) Acceleration a=
t
v−u
=
2
8−4
=2m/s
2
Force =m×a=10×2=20 N