Question

1. A body is allowed to fall freely from a height 4.9m. Find the
time taken by it to reach the ground (1 second)​

Answer 1

Answer:

1 second

Explanation:

$h= 4.9 m\\g = 9.8 m s^{-2}\\ u= 0ms^{-1}$

Let the time taken be t

By second equation of free fall under gravity,

$s = ut + \frac{1}{2} gt^{2}$

Substituting

$4.9 = 0(t) + \frac{1}{2}9.8t^2\\4.9 = 4.9 t^{2}\\t^{2} = \frac{4.9}{4.9} = 1\\t = \sqrt{1} = 1 s$