Question

1. A body is moving with constant speed along the circumference of a circle. At a

certain point on its path, the direction of velocity will be, (a) Along the circumference

(b) Towards the centre of the circle

(c) Away from the centre of the circle

(d) Along the tangent.

2). A girl of mass 40 kg jumps with a horizontal velocity of 5 m/s onto a cart of mass

10kg with friction less wheels, which is already moving with a horizontal velocity 1 m/s

in the opposite direction of motion of the girl. What will be the velocity of the girl, when

the cart moves along with her. (Assume that there is no external unbalanced force

working in the horizontal direction

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Answer 1

Answer:

Explanation:

1d)along the tangent

2) we know that

From law of conservation of momentum

Initial momentum=Final momentum

40kg*5m/s+10kg*-1 m/s=10kg*v+40kg*v

V here is the velocity at which both girl and cart would move

190kgm/s=v(40kg+10kg)

190kgm/s=v*50kg

190/50m/s=v

3.8m/s in the direction along which girl jumped would be the velocity of the girl when cart moves along with her

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