Question

1. A body is moving with uniform acceleration,
and describes 75 m in the 6th second and 115
m in the 11th second. Show that its moves 155
m during the 16th second.
​

Answer 1

Answer:

I not know

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Explanation:dd7tdu5fy

Answer 2

Answer:

Formula used: Sₓ=u+a(n-1/2)

To find the acceleration:

According to the given data at two positions,

the equations we get using the formula and on solving them, we will get

-75 = -u - (11/2)a  → 1 multiplying with (-) on both sides

115 = u + (21/2)a → 2

______________

40 = 0 + 5a

______________

Then, acceleration a = 8 m/s² in 1 (eliminating (-))

We get 75 = u + (11/2)8 ⇒ u = 75-44 = 31 m/s

So, initial velocity, u = 31 m/s

So, at 16th second:

S₁₆ = 31 + (16-1/2)8

     = 31 + 31x4

     = 31+124

     = 155 m

Therefore, at 16th second, the body will be at 155 m. Hence, it is proved.