Question

1. A body moving with a speed of 36 km/h
is brought to rest in 10 s. What is the
negative acceleration and the distance
travelled by the body before coming to rest?
(Ans. 1 m/s, 50 m)
​

Answer 1

Answer:

answer is given in ur question.

Step-by-step explanation:

u = 36km/h = 10m/s .............[1Km/h = 5/18 m/s]

v = 0m/s

Using formula :

v = u + at

10 = 0 + a(10)

=> a = 1 m/s^2.

Now, using formula :

v^2 - u^2 = 2as

0 - 10^2 = 2 (-1) S

=> 2S = 100

=> S = 50m.

I hope it helps u .

Please Mark it as Branliest Answer It will motivate me further.

Answer 2

Answer:

DATA

Step-by-step explanation:

vi = 36km/h or 36×1000÷3600= 10m/s Now our unit is Si system.

Vf = 0 m/s

T = 10s

Negative acceleration = a = ??

d = ????

Solution.

vf = vi + at

0 = 10 + a10

-10 = a10

-10÷10 = a

or

a = -1 negative sign shows acceleration is negative acceleration .. or

a = 1

(2)

2as = vf² _ vi²

S = 0² _ 10² ÷ 2(-1)

S = 0 _ 100 ÷ -2

S = 50 m

I hope you will understand !!!!!!

Mudasir Soomro ...