Question

1 A body of mass 2 kg starting from rest attains a velocity of 10 m/s in 10 s. The force acting on the body is
(1) 20 N
(2) 0.2 N
(3) 2 N
(4) 200 N​

Answer 1

Given

• Mass = 2 kg
• Initial Velocity = 0 m/s
• Final Velocity = 10 m/s
• Time = 10 sec

To Find

• Force acting on the body

Solution

☯ v = u + at

• We shall use the first Equation of motion to find the acceleration of the body

☯ F = ma

• We use this formula to find the force that's applied on the body

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✭ According to the Question:

→ v = u + at

→ 10 = 0 + (a × 10)

→ 10 = 10a

→ 10/10 = a

→ Acceleration = 1 m/s²

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✭ Force Applied :

→ F = ma

→ F = 2 × 1

→ F = 2 N

Answer 2

$\tt { \boxed{answer}} \\ \implies \rm \: v = u + at \\ \\ \implies \rm \: 10 = 0 + (a \times 10) \\ \\ \implies \rm \: 10 = 10a \\ \\ \implies \rm \frac{10}{10} = a \\ \\ \red{ \tt \: acceleratio \: = 1m s ^{2} } \\ \\ \rm \: force \: applied \\ \leadsto f = ma \\ \leadsto \: f = 2 \times 1 \\ \leadsto \: 2n$