1.
A body of mass 2 kg travels according to the law x (n = pi + q + rt where, q = 4ms p = 3m s and r = 5m s3. The force acting on the body at t = 2s is
(A) 136 N
(B) 134 N
(C) 158 N
(D) 68 N
Answers
Answered by
0
Answer:
chjxkg kgcgnxjckbclvjfjoj
Answered by
0
Answer:
136N
Explanation:
Here, x(t)=pt+qt
2
+rt
3
Where p=3ms
−1
,q=4ms
−2
,r=5ms
−3
and m=2 kg
Velocity, v=
dt
dx
=
dt
d
(pt+qt
2
+rt
3
)=p+2qt+3rt
2
Acceleration, a=
dt
dv
=2q+6rt
At t=2s,a=2(4ms
−2
)+6(5ms
−2
)(2s)
=8ms
−2
+60ms
−2
=68ms
−2
The force acting on the body of mass 2 kg is
F=ma=(2kg)(68ms−2 )=136N
Similar questions