Question

1. A body of mass 400 g slides on a rough horizontal surface. If the frictional force is 3 N, then the
magnitude of contact force is (take g = 10ms-)
[ ]
a) 4N
b) 3 N
c)7N
d) 5 N
​

Answer 1

Answer:

Contact force is resultant of Normal reaction and friction.

if the angle made by contact force be θ then cotθ=  

friction

N

​  

 where N is normal reaction which is equal to mg put m=0.4Kg so put N=4N and friction as 3N we get cotθ=  

3

4

​  

 so θas36.87 or nearly 37  

0

 

Option B is correct.

Explanation:

Answer 2

Answer:

ans in attachment mate..