1. A body of mass 5 Kg is moving with a uniform velocity of 10 m/s. It is acted upon
by a force of 20 N. What will be its velocity after 1s? Ans-14m/s
2. A force of 100 N acting on a certain mass for 4s gives it a velocity of 20 m/s. Find the
mass of the body if the body was initially at rest. Ans-20Kg
3. A force of 10 N produces an acceleration of 20 m/s2 on a mass m1 and an acceleration
of 30 m/s2 on a mass m2. What acceleration would the same force provide if both the
masses are tied together? Ans-12m/s2
4. A body of mass 2 Kg is kept at rest. A constant force of 6N starts acting on it. Find
the time taken by the body to move through a distance of 54m. Ans-6s
5. The velocity of a particle of mass 500g changes from 16 m/s to 24 m/s in four
seconds. Assuming that a constant force acts on it find the magnitude of the force.
Ans-1N
6. A motor car of mass 250 Kg is moving with a certain velocity. It is brought to rest by
the application of brakes, within a distance of 18 m when the average resistance being
offered to it is 1000N. What was the velocity of the motor car? Ans-12m/s
7. A body of 10 Kg is moving with the velocity of 5 m/s. Find the momentum
associated with the ball. Ans-50kg m/s
8. How much force is needed to produce an acceleration of 20 m/s2 in a body of mass
500 g? Ans-10N
9. A body of mass 2 Kg is moving with the velocity of 12 m/s. Find the momentum of
the body. Ans-24 kg m/s
10. A body of mass 4 Kg undergoes a change in speed from 30 m/s to 40 m/s. Calculate
increase in momentum. Ans- 40 kg m/s
11. How much force is needed to produce and exhilaration of 2.5 m/s2 in a body of mass
4.0 Kg? Ans-10 N
12. A force of 100N acts on a particle of mass 25 Kg. Find the acceleration of the
particle. Ans-4 m/s2
13. A force of 40 N acts on the most in 5 Kg fo 2s. Find the velocity acquired by the
body. Ans-16 m/s
14. A body of mass 2.5 Kg undergoes a change of velocity 10 m/s in 5s. What is the
force acting on it? Ans-5N
15.A force of 12N acts on a mass of 1.5 Kg at rest for 3s. Find the final velocity and the
movement of the body after 3s. Ans-24 m/s, 36 Kg m/s
16. A force of 20 N acting certain mouse for 2s gives it a velocity of 10 m/s. Find the
mass of the body if the body was initially at rest. Ans-4Kg
17. The velocity of a particle of mass 250 g changes to 10 m/s to 16 m/s in 3s. Assuming
that a constant force acts on it, find the magnitude of the force. Ans-0.5N
18. A Force of 6N acts on a body of mass 1.5 Kg for 2.0 s.Assuming the body to be
initially at rest find:
A) its velocity when the four stops acting,
B) the distance covered in five seconds after the force starts acting. Ans- 8 m/s 32 m
Answers
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Answer:The quantity of the medicine does not exceed three months supply
You should leave your medicine in its original packaging.
Penalties
Lose your goods, prosecution and large financial penalties may apply.
Examples
Benzodiazepines, lorazepam, diazepam, nitrazepam, oxazepam
Exceptions
If you run out of medicine, you will need to either see a Doctor in Australia to have the medicine prescribed and supplied in Australia (if it is available in Australia) or apply for a permit from the Office of Drug Control before you arrange to have medicine sent to you. You must have a permit if ordering these medicines from overseas.
Explanation:edatives include prescription medicines from the benzodiazepines group (eg diazepam, lorazepam).
Like other medicines, you can bring in sedatives so long as:
You are arriving in Australia as a passenger on board a ship or aircraft
The medicine is carried in your accompanied baggage
You carry a letter or copy of your pre
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Answer:
Answer:
Given :
Acceleration of the body = 2 m/s².
Initial velocity of the body = 10 m/s.
Time = 2 s.
To Find :
Final velocity of the body = ?
Solution :
Using first equation of motion :
⇒ v = u + at
⇒ v = 10 + 2*2
⇒ v = 10 + 4
⇒ v = 14 m/s
Hence, the final velocity of the body after 2 seconds are : 14 m/s.
Important Formulas :
v = u + at
s = ut + ½at²
v² - u² = 2as
Average velocity = ∆x/∆t
Average speed = Total path/Total time
Instantaneous velocity = dx/dt
Average acceleration = ∆v/∆t
Instantaneous acceleration = dv/dt
∆x = x2 - x1 (Displacement)
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