1. A body of mass m is moving with a uniform velocity u. A force is
applied on the body due to which its velocity increases from u to v. How
much work is being done by the force?
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Answer:
Using third equation of motion, v2−u2=2as
∴a=2s(v2−u2)
We know F=ma
⟹ F=2sm(v2−u2)
Work done W=Fs
Thus W=2sm(v2−u2)s
W=21m(v2−u2).
This is the work done.
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