Question

1. A body of volume 100 cm weighs 5 kgf in air
It is completely immersed in a liquid of density
1.8 x 10' kg m Find : (i) the upthrust due to liquid
and (ii) the weight of the body in liquid.
plz answer fast it's arget​

Answer 1

Answer:

It is completely immersed in a liquid of density 1-8 x 103 kg m-3. Find : (i) the upthrust due to liquid and (ii) the weight of the body in liquid.

Answer 2

$\huge\underline{\red{\mathbb{ANSWER :-}}}$

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Weight of body in liquid = Actual weight - upthrust

Upthrust exerted =Vρg

Where, V= volume

ρ= density 

g=acc. due to gravity

Upthrust=100×10−9m3×1.8×103kgm−3×10

⇒0.18kgf

So, Weight of body in liquid = Actual weight - upthrust

⇒5−0.18

=4.82kgf

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